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Nuclear Fusion and Fission

From figure 21.4 it is clear that atomic nuclei with $A <
60$ can combine to form more tightly bound nuclei and in so doing release energy. This is called nuclear fusion and it is the process which powers stars.

Figure 21.7: Combined nuclear and Coulomb potentials between two light nuclei. The resulting potential barrier repels the two nuclei unless their kinetic energy is very large. However, if the nuclei are able to overcome this barrier, substantial energy is released.
\begin{figure}\begin{center}
\psfig{figure=fusepot.eps,width=3in}\end{center}\end{figure}

It is not easy to fuse two nuclei. As figure 21.7 shows, the the nuclear force, which is attractive but short in range, and the Coulomb force, which is repulsive, combine to create a potential barrier which must be surmounted in order to release energy from fusion. Nuclei must therefore somehow attain large kinetic energy for fusion to take place. We shall discover later that temperature is a measure of the translational kinetic energy of atoms and nuclei. Therefore, one way to create fusion is to heat the appropriate material to a very high temperature. The interiors of ordinary stars are hot enough to fuse hydrogen into helium. Somewhat hotter stars can create slightly heavier elements. However, we believe that only the interior of a type of exploding star called a supernova is hot enough to create the heavy elements we find in the universe. Thus, the iron in your automobile engine and the copper in your electrical wiring were created in some of the most spectacular explosions in the universe!

It is possible for a heavy nucleus such as uranium, with atomic number and atomic mass number ($Z,A$) to spontaneously fission or split into two lighter nuclei with ($Z' ,A' $) and ( $Z - Z' , A - A'$) if there is a net energy release from this process:

\begin{displaymath}
Q \equiv B(Z - Z' ,A - A' ) + B(Z' ,A' ) - B(Z,A) > 0
~~~ \mbox{(fission possible)} .
\end{displaymath} (22.9)

An energy of order $160 \mbox{ MeV}$ per nucleus can be released by causing uranium ($Z = 92$) or plutonium ($Z = 94$) to fission.

Figure 21.8: Spontaneous fission of a heavy nucleus into a slightly lighter nucleus and an alpha particle occurs when the alpha particle penetrates the potential barrier illustrated by the shading and leaves the nucleus. Other types of spontaneous fission occur in a similar manner. Compared to the case of two light nuclei in figure 21.7, the Coulomb potential is more important here, which makes the resultant force more repulsive.
\begin{figure}\begin{center}
\psfig{figure=sponfission.eps,width=4in}\end{center}\end{figure}

Even if $Q > 0$, spontaneous fission generally occurs at a very slow rate. This is because a potential energy barrier of order $5
\mbox{ MeV}$ typically must be overcome for this split to occur. Barrier penetration allows fission to occur spontaneously in the absence of the energy needed to overcome this barrier, as illustrated in figure 21.8, but is generally a slow process. Alpha decay is an example of spontaneous fission of a heavy nucleus by barrier penetration in which $Z' = 2$ and $A' = 4$.

If a heavy nucleus collides with an energetic particle such as a neutron, photon, or alpha particle, it can be induced to fission if the energy transferred to the nucleus exceeds the approximate $5
\mbox{ MeV}$ needed to breach the potential barrier.

If the heavy nucleus has an odd number of neutrons, another way for fission to occur is for the nucleus to capture a slow neutron, i. e., one with energy much less than the $5
\mbox{ MeV}$ needed to directly overcome the potential barrier. In this case neutron capture actually converts the nucleus from atomic number and mass $(Z,A)$ to atomic number and mass $(Z,A + 1)$.

The binding energy per nucleon of a nucleus with an even number of neutrons is greater than the binding energy per nucleon of one with an odd number, since in the former case all neutron spins are paired. Thus, if the initial nucleus has an odd number of neutrons, the capture of a slow neutron makes it more tightly bound than if the initial nucleus has an even number of neutrons. If the difference in binding energy between the initial nucleus and the nucleus modified by neutron capture exceeds the $5
\mbox{ MeV}$ needed to overcome the potential barrier for spontaneous fission, then energy conservation leaves the new nucleus in a sufficiently high excited state that it instantly fissions. Examples of nuclei subject to fission by slow neutron absorption are uranium 235 and plutonium 239. Note that both have odd numbers of neutrons. In contrast, uranium 238 has an even number of neutrons and slow neutron bombardment does not cause fission.


next up previous contents
Next: Problems Up: Atomic Nuclei Previous: Radioactivity   Contents
D. J. Raymond 2001-05-14