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Input:
dsolve(y'=sin(x+ y))
Write:
`dsolve(y'=sin(x+ y))`
Compute:
$$dsolve(y^{(1)}(x)=sin(x+y))$$
Output:
$$dsolve(y^{(1)}(x)=sin(x+y))== tan(\frac{-1}{2}+\frac{1}{4}\ \pi )-tan(\frac{1}{4}\ \pi -\frac{1}{2}\ (x+y))=C_1+x$$ Result: $$tan(\frac{-1}{2}+\frac{1}{4}\ \pi )-tan(\frac{1}{4}\ \pi -\frac{1}{2}\ (x+y))=C_1+x$$
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