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Input:
solve(mod(x-1,2)=1)
Write:
`solve(mod(x-1,2)=1)`
Compute:
$$solve((-1+x)\ mod \ 2=1)$$
Output:
$$solve((-1+x)\ mod \ 2=1)== f^{-1}((-1+1)\ mod \ 2,1)$$ Result: $$f^{-1}((-1+1)\ mod \ 2,1)$$
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